Seahawks make Russell Wilson the NFL’s highest-paid QB
The Seattle Seahawks and quarterback Russell Wilson have finally settled on a deal that will keep him with the team and make him the NFL’s highest-paid player.
Adam Schefter of ESPN provided financial details, while Ian Rapoport of NFL Network noted there is a no-trade stipulation inserted into the quarterback’s deal:
Russell Wilson and the Seahawks reached agreement on a 4-year, $140 million in new money extension that includes a $65 million signing bonus, per source. https://t.co/SgsxgNIqli
— Adam Schefter (@AdamSchefter) April 16, 2019
Full details for the #Seahawks and QB Russell Wilson: 4 new years, $140M. $65M to sign. Total guarantee: $107M. A no-trade clause. … Now, Wilson is under contract for 5 years and $157M. And staying in Seattle.💰💰💰
— Ian Rapoport (@RapSheet) April 16, 2019
Russell Wilson confirmed on via Twitter account–and in bed with wife, Ciara–that he is set to sign an extension:
SEATTLE. Let’s get it. @Seahawks #GoHawks pic.twitter.com/xeWnEnUzmR
— Russell Wilson (@DangeRussWilson) April 16, 2019
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“Hey, Seattle, we got a deal,” he said. “Go Hawks. But I’ma see y’all in the morning. Time for y’all to go to bed.”
Russell Wilson had set a midnight deadline on April 15 for an extension and the video he posted came 45 minutes after the deadline expired.
He had a year left on his previous deal with the Seahawks, although his representatives reportedly made clear a new contract needed to be agreed to by the deadline. Wilson was set to make $17 million in his final season.
Wilson’s original contract, plus the reported $140 million extension gives him the league’s highest contract value.
